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Yakvenalex [24]
2 years ago
12

SOMOEN HELP ME WITH THAT PLS

Mathematics
2 answers:
alexira [117]2 years ago
5 0
If you download Photomath on your phone it helps a lot!
Wittaler [7]2 years ago
5 0
USE PHOTO MATH IT HELPS A LOT
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Which expression can be used to approximate the expression below,for all positive number a,b and x where a =/ 1 and b=/ 1
rodikova [14]

Answer:

The correct option is 1.

Step-by-step explanation:

The given expression is

log_ax

The value of a is 1 and the value of b is 1.

According to the logarithm property,

log_mn=\frac{log_pm}{log_pn}

Using this property, we get

log_ax=\frac{log_bx}{log_ba}

The required expression is \frac{log_bx}{log_ba}.

log_1x=\frac{log_1x}{log_11}

log_1x=log_1x                   [\because log_aa=1]

Left hand side is equal to the right hand sides, therefore option 1 is correct.

4 0
2 years ago
Find the slope of the line that passes through<br> (10, 1) and (5,2)<br> -5<br> -1/5<br> 1/5<br> 5
rusak2 [61]

Answer:

-1/5 I believe, since you go down one and to the right by 5.

7 0
3 years ago
I need help please if m&lt;MNR=43 and m&lt;MNP=84 find: m&lt;RNP​ subtract or add
Zielflug [23.3K]

Answer:

  41°

Step-by-step explanation:

The angle addition theorem tells you ...

  m∠MNR + m∠RNP = m∠MNP

Filling in the given values, you have ...

  43° + m∠RNP = 84°

Subtract 43° from both sides of the equation to find the angle of interest:

  m∠RNP = 84° - 43° = 41°

The measure of angle RNP is 41°.

7 0
3 years ago
Help idk I don’t understand please ASAP
Pachacha [2.7K]

Answer:

x = 200/3

Step-by-step explanation:

Apply Thales theorem, we have:

80/(2x) = 60/27

Let's simplify both sides:

40/x = 20/9

or

x/40 = 9/20

Multiplying both sides by 40, we have:

(40/40)x = (20/9)*40

Let's simplify one more time:

x = (20*40)/(9)

or

x = 200/3

Hope this helps!

8 0
3 years ago
Read 2 more answers
(2x+2y=10)+(-x+y=1)
ruslelena [56]
\bf \begin{cases}&#10;2x+2y=10\\&#10;-x+y=1&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;-x+y=1\implies y=1+x\impliedby \textit{let's plug that in the first equation}&#10;\\\\\\&#10;2x+2(\stackrel{y}{1+x})=10\implies 2x+2+2x=10\implies 4x=8&#10;\\\\\\&#10;x=\cfrac{8}{4}\implies \boxed{x=2}\impliedby \textit{let's plug that in the second one}&#10;\\\\\\&#10;-(\stackrel{x}{2})+y=1\implies \boxed{y=3}
7 0
3 years ago
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