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Ghella [55]
3 years ago
15

(2x+2y=10)+(-x+y=1)

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0
\bf \begin{cases}
2x+2y=10\\
-x+y=1
\end{cases}\\\\
-------------------------------\\\\
-x+y=1\implies y=1+x\impliedby \textit{let's plug that in the first equation}
\\\\\\
2x+2(\stackrel{y}{1+x})=10\implies 2x+2+2x=10\implies 4x=8
\\\\\\
x=\cfrac{8}{4}\implies \boxed{x=2}\impliedby \textit{let's plug that in the second one}
\\\\\\
-(\stackrel{x}{2})+y=1\implies \boxed{y=3}
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3 0
3 years ago
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The easiest way is to try the point (-4,1), that is, x=-4, y=1,
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b works.

The usual way to do it is to find the equation of the circle
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in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
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