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-BARSIC- [3]
3 years ago
9

Casey bought 9 tickets to a concert. After a $5 service charge, the total cost was $131. Write and solve an equation to find the

cost of each ticket.
please explain
Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer: 14

Step-by-step explanation:

131 (total cost of tickets)- 5 (service charge) = 126 cost of tickets

126/9= 14 dollars a ticket

(c= cost)

131-5=c

126/9=14

Hope this helped

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Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.
serg [7]

Given:

A figure.

To find:

The values of x and y.

Solution:

We know that, in a right angled triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin 60^\circ =\dfrac{x}{16}

\dfrac{\sqrt{3}}{2} =\dfrac{x}{16}

Multiply both sides by 16.

\dfrac{\sqrt{3}}{2}\times 16=\dfrac{x}{16}\times 16

8\sqrt{3}=x

And,

\cos \theta =\dfrac{Base}{Hypotenuse}

\cos 60^\circ =\dfrac{y}{16}

\dfrac{1}{2}=\dfrac{y}{16}

Multiply both sides by 16.

\dfrac{16}{2}=y

8=y

Therefore, the missing side lengths are x=8\sqrt{3} and y=8.

6 0
3 years ago
The question is in the picture above^
harkovskaia [24]
Man.I can’t help you..sorry
5 0
3 years ago
Larry and Paul start out running at a rate of 5 mph. Paul speeds up his pace after 5 miles to 10 mph but Larry continues the sam
klasskru [66]
<h2>Hello!</h2>

The answer is:

They will be 10 miles apart after 3 hours.

<h2>Why?</h2>

To calculate how long after they start will they be 10 miles apart, we need to assume that after 1 one hour, they were at the same distance (5 miles), then, calculate the time when they are 10 miles apart, knowing that Paul increased its speed two times, running first at 5mph and then, at 10 mph.

The time that will pass to be 10 miles apart can be calculated using the following equation:

TotalTime=TimeToReach5miles+TimeToBe10milesApart

Calculating the time to reach 5 miles for both Larry and Paul, at a speed of 5 mph, we have:

x=xo+v*t\\\\5miles=0+5mph*t\\\\t=\frac{5miles}{5mph}=1hour

We have that to reach a distance of 5 miles, they needed 1 hour. We need to remember that at this time, they were at the same distance.

If we want to know how many time will it take for them to be 10 miles apart with Paul increasing its speed to 10mph, we need to assume that after that time, the distance reached by Paul will be the distance reached by Larry plus 10 miles.

So, for the second moment (Paul increasing his speed) we have:

For Larry:

x_{L}=5miles+5mph*t

Therefore, the distance of Paul will be equal to the distance of Larry plus 10 miles.

For Paul:

x{L}+10miles=xo+10mph*t\\\\5miles+5mph*t+10miles=5miles+10mph*t\\\\5miles+10miles-5miles=10mph*t-5mph*t\\\\10miles=5mph*t\\\\t=\frac{10miles}{5mph}=2hours

Then, there will take 2 hours to Paul to be 10 miles apart from Larry after both were at 5 miles and Paul increased his speed to 10 mph.

Hence, calculating the total time, we have:

TotalTime=TimeToReach5miles+TimeToBe10milesApart

TotalTime=1hour+2hours=3hours

Have a nice day!

3 0
4 years ago
I need this ASAP!!!! PLZ HELP!!! 20 points!!
sergiy2304 [10]
Answer:

Third graph C.

Step-by-step explanation:

3a + 11 > 5

Subtract 11 from both sides

3a > -6

Solve for a

a = -6/3

a > -2

so a would be all numbers greater than -2
7 0
3 years ago
Read 2 more answers
What is the distance between points A(3, 8) and B(-3, 4)?
max2010maxim [7]

Answer:

About 7.2 OR (7.211102551)

Step-by-step explanation:

8 0
3 years ago
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