Question

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?

Answer 1

Answer:

$\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}$

Step-by-step explanation:

We know that for any two function f(x) and g(x) ,

$\dfrac{f}{g}(x)=\dfrac{f(x)}{g(x)}$

Given functions : $r(x)=3x-1$  and $s(x)=2x+1$

Then, $\dfrac{r}{s}(x)=\dfrac{r(x)}{s(x)}$

$\Rightarrow\ \dfrac{r}{s}(x)=\dfrac{3x-1}{2x+1}$

At x= 6 , we get

$\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}$

The , The expression is equivalent to $\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}$

When we further simplify it , we get $\dfrac{r}{s}(6)=\dfrac{18-1}{12+1}=\dfrac{17}{13}$