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jenyasd209 [6]
3 years ago
14

D = 13 in. Radius =

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

6.5 in

Step-by-step explanation:

D = 2r

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How can I find the diagonals?
irga5000 [103]

Answer:

squaring the both side

6 0
4 years ago
Which values for a and b make the statement (a+6) (b-1)=0 true?
alexdok [17]

Answer:

The answers A, B, and C all work for this problem. The answer D is the only one that does not.

Step-by-step explanation:

When looking at two parenthesis being multiplied together and being equal to 0, we know that at least one of the parenthesis must be equal to 0 for it to be true. In A and C, the first parenthesis will be equal to 0 due to a = -6.

(a + 6)

(-6 + 6)

(0)

And in B, we can see that the second parenthesis would be equal to 0 due to b = 1

(b - 1)

(1 - 1)

(0)

Now we can try the D options, but will note that they do not work for either parenthesis.

(a + 6)(b - 1)

(0 + 6)(0 - 1)

(6)(-1)

4 0
3 years ago
What is the difference between a^3+b^3 and (a+b)^3?
mylen [45]
There is no different in both of them. if you used both of them in a math problem you would still get the same answer as if you use the other one.
5 0
4 years ago
Read 2 more answers
John ordered five large size pizzas for a party. Five kids each ate 1/10 slice, and twelve adults each at 3/10 slices.
astraxan [27]

Answer:

a) 4 1/10 slices eaten

b) cannot be solved because we don't know how many slices in each pizza

Step-by-step explanation:

5*1/10=5/10

12*3/10=36/10

36/10+5/10=41/10

41/10=4 1/10 slices

8 0
3 years ago
Suppose that is an angleand y is not in the first quadrant. Compute the exact value of secyYou do not have to rationalize the de
Pavel [41]

ANSWER :

The answer is :

-\frac{5\sqrt{10}}{9}

EXPLANATION :

Note that cotangent is only positive when the angle is in the first or third quadrant.

Since y is not in the first quadrant, it must be in the third quadrant.

So the x and y are both negative.

An angle with a terminal point (x, y)

The cotangent is x/y

We can equate :

\cot\gamma=\frac{9}{13}=\frac{x}{y}

Since x and y are both negatives, x = -9 and y = -13

We can have the triangle :

The hypotenuse will be :

\begin{gathered} c=\sqrt{(-9)^2+(-13)^2} \\ c=5\sqrt{10} \end{gathered}

We are asked to find the value of sec y.

In an angle with a terminal point (x, y)

The secant is :

\sec\gamma=\frac{\text{ hypotenuse}}{x}

The hypotenuse is 5√10 and x = -9

The value of sec will be :

\begin{gathered} \sec\gamma=\frac{5\sqrt{10}}{-9} \\  \\ =-\frac{5\sqrt{10}}{9} \end{gathered}

6 0
1 year ago
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