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3 years ago

Pls help me the question is in the photo !!

Mathematics

1 answer:

Karolina [17]3 years ago

5 0

Answer:

Step-by-step explanation:

separate the figure into two shapes. On the little one is 2x1 which the answer is 2 then on the larger shape is 6x2 which is 12 then you add 12+2 and then you get your answer

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Alisiya [41]

Answer:

39.5

Step-by-step explanation:

it's how many times 0.08 goes into 3.16

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3 years ago

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What is the basic numbers of pi

MAXImum [283]

Answer:

3.14

Step-by-step explanation:

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4 years ago

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What is the circumference of a circle with a diameter of 7 in

morpeh [17]

Answer:

22 inches

Step-by-step explanation:

Given:

Diameter - 7 inches
Radius - 3.5 inches

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2 years ago

Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.

qwelly [4]

Answer:

$\displaystyle \frac{dy}{dt}=-\frac{33}{8}$

$\displaystyle \frac{dx}{dt}=\frac{3}{2}$

Step-by-step explanation:

x and y are differentiable functions of t, and we are given the equation:

$xy=6$

First, let's differentiate both sides of the equation with respect to t. So:

$\displaystyle \frac{d}{dt}\left[xy\right]=\frac{d}{dt}[6]$

By the Product Rule and rewriting:

$\displaystyle \frac{d}{dt}[x(t)]y+x\frac{d}{dt}[y(t)]=0$

Therefore:

$\displaystyle y\frac{dx}{dt}+x\frac{dy}{dt}=0$

We want to find dy/dt when x = 4 and dx/dt = 11.

Using our original equation, find y when x = 4:

$\displaystyle (4)y=6\Rightarrow y=\frac{3}{2}$

Therefore:

$\displaystyle \frac{3}{2}\left(11\right)+(4)\frac{dy}{dt}=0$

Solve for dy/dt:

$\displaystyle \frac{dy}{dt}=-\frac{33}{8}$

We want to find dx/dt when x = 1 and dy/dt = -9.

Again, using our original equation, find y when x = 1:

$(1)y=6\Rightarrow y=6$

Therefore:

$\displaystyle (6)\frac{dx}{dt}+(1)\left(-9)=0$

Solve for dx/dt:

$\displaystyle \frac{dx}{dt}=\frac{3}{2}$

5 0

3 years ago

2n+(7n+8)= what is the missing coefficient

Taya2010 [7]

Assuming that you were to simplify this, you'd get 2n + 7n + 8 = 9n + 8.

6 0

3 years ago