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Ivahew [28]
3 years ago
13

The table shows the height of water in a pool as it is being filled. A table showing Height of Water in a Pool with two columns

and six rows. The first column, Time in minutes, has the entries, 2, 4, 6, 8, 10. The second column, Height in inches, has the entries, 8, 12, 16, 20, 24. The slope of the line through the points is 2. Which statement describes how the slope relates to the height of the water in the pool?
A. The height of the water increases 2 inches per minute.
B.The height of the water decreases 2 inches per minute.
C. The height of the water was 2 inches before any water was added.
D. The height of the water will be 2 inches when the pool is filled.
Mathematics
1 answer:
defon3 years ago
5 0

Answer:

A. The height of the water increases 2 inches per minute.

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How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
5 0
3 years ago
If ∆BCD ~ ∆GEF, find the value of x.
Karolina [17]
X=48
Y=44
Because the triangles are congruent.
8 0
2 years ago
Read 2 more answers
I need to know if it’s A B C OR D
Liula [17]

SOLUTION

Consider the property, opposite angle of a cyclic quadrilateral are supplementary

hence

\angle NMP+\angle NOP=180^0

Recall that

\begin{gathered} \angle NMP=\angle M=(8x-24)^0 \\ \text{and } \\ \angle NOP=\angle O=(4x)^0 \end{gathered}

Hnece, we have that

\begin{gathered} \angle M+\angle O=180^0(opposite\text{ angles of a cyclic quadrilateral)} \\ (8x-24)^0+4x^0=180^0 \end{gathered}

Then

\begin{gathered} 8x-24+4x=180 \\ 8x+4x-24=180 \\ 12x-24=180 \\ \text{Add 24 t o both sides } \\ 12x-24+24=180+24 \\ 12x=204 \\ \text{divide both sides by 12} \\ \frac{12x}{12}=\frac{204}{12} \\ \text{Then} \\ x=17 \end{gathered}

Hence

x=17

Since

\begin{gathered} \angle NOP=(4x)^0 \\ \text{substitute the value of x, we have } \\ \angle NOP=4\times17=68^0 \\ \text{Hence } \\ \angle NOP=68^0 \end{gathered}

Therefore

The measure of angle NOP is 68⁰

Answer; 68⁰ (The fourth Option )

5 0
1 year ago
2 (2x + 3 = 1)<br> 7 — бу = 20
max2010maxim [7]

Answer:

x = -1    y =  - 13/6

Step-by-step explanation:

4 0
3 years ago
Describe a real world problem that you could solve using the volume of spheres
alexgriva [62]

A toy company produces rubber balls that have a radius of 1.7 cm.

What is the volume of one rubber ball? Round to the

nearest hundredth of a centimeter.

20.58 cm3

If the price of the rubber needed to produce a ball is

$0.0045/cm3, what is the cost of producing one ball?

Round to the nearest cent.

If the company sells a ball for $0.50, how much profit

will it make on each ball?

$1.7 cm

20.58 cm^3, $0.09, $0.41

Hope this helps

5 0
2 years ago
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