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Kaylis [27]
3 years ago
13

Plz help me! I suck at math!

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

(-2,4)

Step-by-step explanation:

Since this is a downward facing parabola, the vertex is the maximum

The maximum is at (-2,4)

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please and thank you I just need someone to correct my work from my answer to the answer my teacher wrote I'M CONFUSED AND NEED
Ludmilka [50]

Answer:

See below.

Step-by-step explanation:

I'll work it out myself,  then we should be able to see the mistake:-

6 ∛ (64x^5y^9)

= 6 * 4 * x^(5/3) * y^3

= 24 x^(3/3) * x^(2/3) y^3

= 24 x y^3 ∛(x^2)

You've got confused withe the cube root  (∛) on the first line. You've interpreted it   as ' 3  times the square root' so you were on the wrong road from the beginning.

Note that y^9 has cube root y^(9/ 3) = y^3  and x^5 has cube root of x^(5/3).   The square root of x^9 is x^(9/2).

5 0
3 years ago
Practice for the Test Jeremiah is giving away his sports card collection to some of his friends. What is the maximum number of f
DedPeter [7]

Answer:

8 friends

Step-by-step explanation:

each get 3 football cards and 4 baseball cards

use hcf method (highest commen factors)

7 0
2 years ago
Why should you try to make an equivalent fraction with a multiple of ten as your denominator
Anna11 [10]

maybe you would do that because 10 divides by multiple things and is a number with a zero as the 2nd digit so you can multiply it by 10 or 100 or 1000 and add a zero to the numerator to make it bigger

3 0
4 years ago
On a circle, which of these is not a straight line?
Y_Kistochka [10]

Answer:

circumference

Step-by-step explanation:

it's a circle

6 0
3 years ago
Use the diagram to find the value of x to the nearest tenth of a foot.
Olenka [21]

Answer:

a

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan15° = \frac{opposite}{adjacent} = \frac{20}{x} ( multiply both sides by x )

x × tan15° = 20 ( divide both sides by tan15° )

x = \frac{20}{tan15} ≈ 74.6 ft ( to the nearest tenth of a foot )

7 0
3 years ago
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