Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
Step-by-step explanation:
given a point 
the equation of a line with slope m that passes through the given point is
or equivalently
.
Recall that a line of the form 
, the y intercept is b and the x intercept is 
.
So, in our case, the y intercept is 
and the x intercept is 
.
In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph 
. Which means that 
The slope of the tangent line is given by the derivative of the function evaluated at 
. Using the properties of derivatives, we get
. So evaluated at we get 
Replacing the values in our previous findings we get that the y intercept is
The x intercept is
The triangle in consideration has height 
and base 
. So the area is
So regardless of the point we take on the graph, the area of the triangle is always 2.
Answer:
A
Step-by-step explanation:
5y=32
trying to get y by itself
y=32/5
32/5 is the same as 6 and 2/5
pls mark me brainliest
X= -10
You may review the image Ive attached to see how I got this answer.
Length = 3 in * 64 =192
: 1 foot = 12 inches
192 : 12 = 16 ft
Answer:
The true length of a vehicle is 16
good luck and may i be marked as brainliest please
