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Oksana_A [137]
2 years ago
6

Someone ols help tysm if you dk im new :D

Mathematics
2 answers:
eduard2 years ago
6 0
The answer is -41

Explanation:
den301095 [7]2 years ago
4 0

Answer:

-35-6=-41

that's the answer

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What are one dimensional figures
agasfer [191]
Hello!

In geometry there are three dimensions.

Something that is one dimensional is neither flat, wide, or tall. It is just a line.
——————————————
Something two dimensional is flat and wide but has no height. An example of this is a square.

Something three dimensional is wide and tall, and has flat faces. An example is a cube.

To answer your question something one dimensional is something that is not flat, wide, or tall, such as a line.

Hope this helped!
3 0
3 years ago
((10 - 3)2 + 7)- 4 + 62
Snowcat [4.5K]
The answer for this question is 79 :)
3 0
2 years ago
Read 2 more answers
Which of the statements about the following quadratic equation is true?
Sedaia [141]
After manipulating above equation we get, 2x^2 - 7x - 8= 0. Discriminant= b^2 - 4ac = (-7)^2 - 4(2)(-8) = 113>0. So there are 2 real roots :)
3 0
3 years ago
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Solve (i) 4/15+x=17/30​
Anna007 [38]

Answer:

3/10

Step-by-step explanation:

4/15+x=17/30

x=17/30-4/15

x=17/30-8/30

x=9/30

simplify

x=3/10

3 0
2 years ago
A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando
Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744  

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) \times p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = \frac{\text { number of good coils }}{\text { total number of coils }}

Hence, p(getting 2 good coil for two selection) = \frac{88}{100} \times \frac{88}{100} =\bold{0.7744}

5 0
3 years ago
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