Find the slope of a line parallel to each given line. y=-5/3x+5
2 answers:
Answer:
Step-by-step explanation:
First, identify the slope of the line given.
This line is in slope-intercept form or y=mx+b where m is the slope and b is the y-intercept. The number being multiplied by x is the slope. The number being added or subtracted is the y-intercept.
-5/3 is the coefficient to x (-5/3 and x are being multiplied). So, the slope must be -5/3.
Next, remember that parallel lines have equal slopes. If the line is parallel to y= -5/3x+5, the slope must also be -5/3.
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<h3>Answer: Choice B) x = 65, y = 10</h3>
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Work Shown:
The upper pair of angles 60 degrees and (2x-y) degrees are supplementary angles. This is because of the parallel lines. Note how they are same side interior angles. Therefore, (2x-y) and 60 combine to 180 degrees like so
(2x-y)+60 = 180
2x-y = 180-60 ... subtract 60 from both sides
2x-y = 120 ... call this equation 1
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Similarly, (2x+y) and 40 also combine to 180
(2x+y) + 40 = 180
2x+y = 180-40 ... subtract 40 from both sides
2x+y = 140 ... call this equation 2
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Line up equation 1 and equation 2. Then add straight down
That becomes 4x = 260 which solves to x = 65 when you divide both sides by 4.
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If x = 65, then,
2x-y = 120
2(65)-y = 120
130 - y = 120
-y = 120-130
-y = -10
y = 10
or
2x+y = 140
2(65)+y = 140
130+y = 140
y = 140-130
y = 10
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Either way end up with x = 65 and y = 10