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2 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Varvara68 [4.7K]2 years ago

5 0

Answer:

Step-by-step explanation:

These are functions, the number in the parentheses shows you what number you will replace x with

If f(x) = x + 3, then f(-1) is -1 + 3

So, -1 + 3 = 2. g(2) = 2(2) + 1 = 4 + 1 = 5

Hope this helps friend.

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Geometry question 3, Thanks if you help!

Deffense [45]

Answer:

A≈176.71

Step-by-step explanation:

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3 years ago

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A particle moves with velocity vector

asambeis [7]

Answer:

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}$

Step-by-step explanation:

We are given that velocity vector of a particle

$\vec{v(t)}=t\hat{i}-2\hat{j}+t^2\hat{k}$

When t=0 then the particle is at the point (0,-1,1).

We have to find the position of particle at time t.

We know that

Velocity = $\frac{Displacement }{time}=\frac{ds}{dt}$

Therefore, $\vec{v}=\frac{\vec{ds}}{dt}$

$\int{ds}=\int (t\hat{i}-2\hat{j}+t^2\hat{k})dt$

Integrate on both sides then we get

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}+C$

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Substitute the value of point at time t=0 then we get

C= $-\hat{j}+\hat{k}$

Substitute the value of C then we get

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}-\hat{j}+\hat{k}$

Therefore, the position of particle at time t

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2 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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.<br> José trabajo solo 3 horas en un día, ¿qué fracción del día trabajo?

Angelina_Jolie [31]

Usando conceptos de fracciones y proporciones, se encuentra que trabajó $\mathbf{\frac{1}{8}}$ del día.

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Esta pregunta se resuelve por proporciones, usando una regla de tres

Un día completo tiene 24 horas
¿Cuál es la fracción correspondiente a 3 horas de un día?

1 dia - 24 horas

x dias - 3 horas

Aplicar multiplicación cruzada:

$24x = 3$

$x = \frac{3}{24}$

$x = \frac{1}{8}$

Entonces, $\frac{1}{8}$ es la fracción.

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