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Bess [88]
3 years ago
9

What is the constant proportionality of this problem

Mathematics
2 answers:
GaryK [48]3 years ago
8 0
You did not include the problem therefore i cannot help you with this but if you could message me the problem i’d be happy too
ddd [48]3 years ago
3 0
Send the picture next time
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Marysya12 [62]

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Alexeev081 [22]

Answer:

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{(\sin(a)+ \cos(b)})^{2}  =  \\{\sin(a)}^{2}  + 2\sin(a)\cos(b)\\ +  {\cos(b)}^{2}  \\  {(\sin(a) - \cos(b)})^{2}  =  \\{\sin(a)}^{2}   - 2\sin(a)\cos(b) +  {\cos(b)}^{2}

2\sin(a)\cos(b) cancel :\ out\\

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