Ask question

Ask question

All categories

tekilochka [14]

2 years ago

12

To conduct an experiment, researches randomly select six students from a class of 20. How many different groups of six students

are possible?

1 answer:

enot [183]2 years ago

8 0

Answer:

3.33

Step-by-step explanation:

20 divided by 6 equals 3.33333333333

Round that you get 3.33

You might be interested in

the smallest known bacteria are from a genus mycoplasma and can measure as small as 300 nanometers in diameter. given that 1 met

vesna_86 [32]

Length of 1 = 300 = 3 *10^2 nanometers
= 3*10^2/1*10^9 m
= 3*10^(2-9)
= 3*10^-7m

3 0

3 years ago

Read 2 more answers

6(v+2) - 7v = 6 + 5v

slava [35]

Answer:

v = 1

Step-by-step explanation:

6(v+2) - 7v = 6 + 5v

open Parentheses

6*v=6v

6*2=12

New equation:

6v + 12 - 7v = 6 + 5v

simplify

12 - v = 6 + 5v

match like terms

6 = 6v

solve

1 = v

4 0

3 years ago

Read 2 more answers

( image attached) plz help 50 point test ASAP(:

Shtirlitz [24]

A vertical line i believe since x is constant

4 0

2 years ago

Read 2 more answers

What os the answer to 14÷2.5=

almond37 [142]

Answer:

5.6

Step-by-step explanation:

by dividing

6 0

2 years ago

Read 2 more answers

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

2 years ago