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3 years ago

THIS IS FOR MY TEST PLEASE HELP

1 answer:

7 0

2(3x+4y) = 2(24)
6x+8y = 48
Add both the equations
6x + 8y = 48
+ x - 8y = -20
—————————
7x = 28
x = 28/7
x = 4

Plug in this value in the second equation

(4) - 8y = -20
-8y = -24
y = -24/-8
y = 3

Therefore:
x = 4
y = 3

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Form a sequence that has two arithmetic means between -1 and 59.

9966 [12]

Answer:

Correct choice is B

Step-by-step explanation:

For the numbers -1 and 59, find the difference 59-(-1):

since 59-(-1)=60 and $\dfrac{60}{3}=20$ (two arithmetic means tells you there will be three intervals), two arithmetic means will be

-1+20=19;
19+20=39.

The only correct sequence is -1, 19, 39, 59.

7 0

3 years ago

Read 2 more answers

Plz help with this I don’t really get it

Greeley [361]

Answer:

Step-by-step explanation:

Associative Property of Multiplication is a(bc) = (ab)c

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6 0

3 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

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3 years ago

(9 1/3 + 4 2/3) +7 - (-12)= A: 2 and 5/8 B: -13 and 13/16 C: 14 D: 4

SSSSS [86.1K]

Answer:

BIL is the answer to that one day

7 0

3 years ago

I need help with letter B, please!

Gala2k [10]

So if you want to fit the y-intercepts or "b", on the y-axis you should go by 25's [0, 25, 50, 75, 100...]

If the x-axis does not have to follow the same pattern (25's), you should go by 5's [0, 5, 10, 15, 20...]

y = 7x + 50

y = 2x + 175

First I would plot the y-intercepts for each equation, then plot a few points with x = 5, 10, 15 Then draw a straight line.

The point where the two lines meet/cross paths is your solution. It should be (25, 225) The x-axis is the number of miles, and the y-axis is the total cost. So Truck driver A and B would arrive/be at the same place/meet in 25 miles at the same cost of $225

5 0

3 years ago