Answer:
152 times 6=912
Step-by-step explanation:
$120 for every 20 students
it cost $6 for every 1 student
$6 times 152=912
My key can’t perform this but I can solve it on a sheet...
So here I really hopes this helps
The answer is 10x^4 - 2x ^3
Here, we are required to determine after how many minutes will the two substances be at the same temperature.
The equation of when the two substances will be at the same temperature and the solution are as follows;
(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).
(b) The solution is, x = 3.285minutes.
For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;
For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;
(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).
The equation is therefore;.
96.2 + 1.5(x) = 98.5 + 0.8(x)
(b) To determine the solution;
1.5x - 0.8x = 98.5 - 96.2
0.7x = 2.3
x = 2.3/0.7
x = 3.285minutes.
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