Answer:
34g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H2S + 2AgNO3 —> 2HNO3 + Ag2S
Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.
This is illustrated below:
From the balanced equation above,
We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.
Finally, we shall convert 1 mole of H2S to grams. This is shown below:
Number of mole H2S = 1 mole
Molar mass of H2S = (2x1) + 32 = 34g/mol
Mass = number of mole x molar Mass
Mass of H2S = 1 x 34
Mass of H2S = 34g
Therefore, 34g of H2S is needed to react with 2 moles of AgNO3.
The standard ambient temperature and pressure are
Temperature =298 K
Pressure = 1atm
The density of gas is 1.5328 g/L
density = mass of gas per unit volume
the ideal gas equation is
PV = nRT
P = pressure = 1 atm
V = volume
n = moles
R= gas constant = 0.0821 Latm/mol K
T = 298 K
moles = mass / molar mass
so we can write
n/V = density / molar mass
Putting values
Thus molar mass of gas is 37.50g/mol
Answer:
The electron pair geometry is Trigonal planar
Molecular geometry - Bent
Approximate bond angle - <120°
Explanation:
The valence shell electron pair repulsion theory enables us to predict the shapes of molecules based on the number of electron pairs present on the valence shell of the central atom and based on the hybridization state of the central atom.
sp2 hybridization corresponds to trigonal planar geometry. Let us recall that the presence of lone pairs causes a deviation of the molecular geometry from the expected geometry based on the number of electron pairs.
Hence, owing to one lone pair present, the observed molecular geometry is bent.
Answer:
500 meters per squared second
Explanation:
The difference in speed between 2000 and 6000 is 4000. You divide the velocity by the time, which in this case is 8. So 4000 divided by 8 is 500 meters per second squared.
Answer:
You forget to compute the calculation systematically.
101.325 J/L*atm is obtained by dividing R in J/(mol*K) with R in L*atm/(mol*K)
Explanation:
Fo the given equation
Wrev = -nRtln(vf/vi)
We have the calculation below:
Wrev = -(1.000 mol)(0.08205 L*atm/mol*K)(298K)ln(10L/1L)
Wrev = -24.4509*ln(10) = -24.4509*2.303 = -56.3 L*atm
However, the unit was converted from L*atm to J by using a conversion unit derived from the ratio of gas constant (R) in J/(mol*K) and L*atm/(mol*K).
R = 0.082057 L*atm/(mol*K)
R = 8.3145 J/(mol*K)
Therefore, we can derive a conversion unit for L*atm to J as:
[8.3145 J/(mol*K)]/[0.082057 L*atm/(mol*K)] = 101.325 J/L*atm
Thus:
Wrev = -56.3 (L*atm) * 101.325 (J/L*atm) = -5705 J