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dexar [7]
4 years ago
12

What is the final temperature of a 27.2-gram wooden block that starts at 23.4°C and loses 759 joules of energy? The specific hea

t capacity of wood is 1.716 joules/gram degree Celsius. Use the formula Q = mCΔT.
A. 7.1°C
B. 10.9°C
C. 16.3°C
D. 39.7°C
Chemistry
1 answer:
sattari [20]4 years ago
6 0

T = final temperature  of the block

T₀ = initial temperature of the block = 23.4 °C

Q = energy lost  from the wooden block = - 759 J

c = specific heat capacity of wood = 1.716 J/(g  °C)

m = mass of the wooden block = 27.2 g

Heat lost from the block is given as

Q = m c (T - T₀)

inserting the values

- 759 = (27.2) (1.716) (T - 23.4)

T = 7.1 °C

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I have attached the structure of Butanoic Acid. Please refer to the attachment.

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