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2 years ago

1) (x - 2)/(x - 3) + (3x - 11)/(x - 4) = (4x + 13)/(x + 1)

Mathematics

1 answer:

mote1985 [20]2 years ago

7 0

Step-by-step explanation:

or,(x-2)(x-4)+(3x-11)(x-3)/(x-3)(x-4)=(4x+13)/(x+1)

or,x^2-4x-2x+8+3x^2-9x-11x+33/x^2-4x-3x+12=(4x+13)/(x+1)

or,4x^2-4x-2x-9x-11x+8+33/x^2-7x+12=(4x+13)/(x+1)

or,4x^2-26x+41/x^2-7x+12=(4x+13)/(x+1)

or, (x+1)(4x^2-26x+41)=(4x+13)(x^2-7x+12)

or,4x^3-26x^2+41x+4x^2-26x+41=4x^3-28x^2+48x+13x^2-91x+156

or,-26x^2+4x^2+28x^2-13x^2+41x-26x-48x+91x=156-41

or,-7x^2+58x=115

or,-7x^2+58x-115=0

or,-(7x^2-58x+115)=0

or,7x^2-58x+115=0

or,7x^2-(35+23)x+115=0

or,7x^2-35x-23x+115=0

or,7x (x-5)-23 (x-5)=0

or, (x-5)(7x-23)=0

Either, Or,

(x-5)=0 (7x-23)=0

or,x=0+5 or,7x=23

:x=5 :x=23/7

Hence,x=5 or 23/7

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3 years ago

1) (x - 2)/(x - 3) + (3x - 11)/(x - 4) = (4x + 13)/(x + 1)​

1) (x - 2)/(x - 3) + (3x - 11)/(x - 4) = (4x + 13)/(x + 1)