Answer:
y=36/9 or y=4
Step-by-step explanation:
3x=15: x=5
y=7(5)+1/3(5)-6
y=36/15-6
y=4
Answer:
135°, 63°, 63°, 99°
Step-by-step explanation:
Find attached the diagram used in solving the question.
We would use formula for sum of interior angles to get each exterior angle.
From the diagram, we added additional variables to be able to solve for sum of interior angles.
Sum of angle on a straight line = 180°
a° +15z° = 180°
b° +7z° = 180°
c° +7z° = 180°
d° +11z° = 180°
Where a,b,c and d are interior angles
Sum of interior angles = 180(n-2)
n = number of sides
For quadrilateral, n= 4
a°+b°+c°+d° = 180(n-2)
180-15z +180-7z+180-7z+180-11z = 180(4-2)
720-40z = 180(2)
720 - 360 = 40z
z = 360/40
z = 9
Each exterior angle:
15z = 15×9 = 135°
7z = 7×9 = 63°
7z = 7×9 = 63°
11z = 11×9 = 99°
<span>It led to an intensification of the nuclear arms race. </span>
For Ryan it would be 5.95=4t+m
For Seth it would be 6.95=3t+2m
1.So next you would figure out just one of the prices by moving the equation around and getting just one variable on each side: m=5.95-4t
2. Substitute that into the second equation and solve: 6.95=3t+2(5.95-4t) then
6.95=3t+11.9-8t (subtract 11.9 from each side) -4.95=-5t (divide each side by 5) t=.99
3. now you know each each tv show is 99 cents. now substitute that into the equation and solve: 6.95=3(.99)+2m then 6.95=2.97+2m (subtract 2.97 from each side) 3.98=2m (divide each side by 2) m=1.99
4. now you know each music video is $1.99 each. check your answer by substituting in each equation:
5.95=4(.99)+(1.99) 5.95=5.95 yes!
6.95=3(.99)+2(1.99) 6.95=6.95 yes!
5. solve in a full sentence: The website charges $0.99 to download a television show and $1.99 to download a music video
Answer:
EAB= DCB
Step-by-step explanation:
Since EAB and DCB are two right triangles then the figure ACDE is rectangular. since the total sum of rectangular 360° there is no options except to be rectangular. If the figure ACDE is rectangular then the two sides AE & CD are equal. Since Point b is midway point the two sides are also equal.
