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3 years ago

8. TEMPERATURE To convert a temperature in degrees Celsius to degrees

Mathematics

1 answer:

Evgen [1.6K]3 years ago

4 0

Answer:

do you know the answer

Step-by-step explanation:

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to make pink paint, sylvia mixes 7 cups of white paint to every 3 cups of red paint. which table shows possible values of w, the

-BARSIC- [3]

Answer: A

Step-by-step explanation:

For every 3 cups she need 7 cups of white paint.

answer a displays that with 3*2=6 and 7*2=14

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2 years ago

What is 16.5 as a percent and NO it is not 165% or 1650% none of that please

sveticcg [70]

I could be wrong but .165% would be my guess it it’s not 165% or 1650%

6 0

2 years ago

If yall help me with all the answers ill give you 32 points. Ik this is easy but I'm too lazy to do this. someone help me, pleas

Anna007 [38]

Answer:

100-both

75-5

565- 5

2815- 5

10050- both

57- 3

1365- 3

14- 2

81- 3

3850- 2

333- 9

1125- 9

448- 8

630- 9

5496- 8

114- 6

21,750- 6

3580- 4

2528- 4

944- 4

Step-by-step explanation:

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3 years ago

What is (x² + 7x + 6) divided by (x + 1)? X-6 - 7 X + 6 x + 7 need answer ASAP

hram777 [196]

Answer:

Step-by-step explanation:

hello :

x+6 because : (x+6)(x+1) =x²+x+6x+6=x² + 7x + 6)

7 0

2 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

2 years ago