answer : option C
Lets find the number of zeros by factoring
Group first two terms and last two terms
Factor out GCF from each group
Now we set each factor =0 and solve for x
0 = (x^2-8) and (x + 1)=0
and x = -1
and x= -1
So we have three real zeros
The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.
Answer:
125x - 33x⁴
Pull out like factors :
125x - 27x⁴ = -x • (27x3 - 125)
Factoring: 27x³- 125
Theory : A difference of two perfect cubes, a³ - b³ can be factored into
(a-b) • (a² +ab +b²)
(a-b)•(a²+ab+b²) =
a³+a²b+ab²-ba²-b²a-b³ =
a³+(a2b-ba²)+(ab²-b²a)-b³ =
a³+0+0+b³ =
a³+b³
Check : 27 is the cube of 3
Check : 125 is the cube of 5
Check : x³ is the cube of x¹
Factorization is :
(3x - 5) • (9x² + 15x + 25)