Please help me complete this math problem, thank you very much!!!

Mathematics

1 answer:

Makovka662 [10]3 years ago

4 0

Answer:

B. 230

Step-by-step explanation:

The formula is 2(wl+hl+hw).

Use this formula for every rectangular prism.

You might be interested in

Which shows the correct substitution of the values a,b,and c from the equation 0=4x^2+2x-1 into the quadratic formula below

lutik1710 [3]

Given quadratic equation : $0 = 4x^2+2x- 1$

Let us apply standard quadratic form $0=ax^2+bx+c$

We know, quadratic formula

$x = \frac{-b+-\sqrt{b^2-4ac}}{2a}$

a = 4

b = 2

c= -1

Now we plug in all the values in quadratic formula

$x = \frac{-b+-\sqrt{b^2-4ac}}{2a} \\ x = \frac{-2+-\sqrt{2^2-4(4)(-1)}}{2(4)}\\ x = \frac{-2+-\sqrt{18}}{8}$ .

<h3>The above one is the substitution of values of a,b,c in quadratic formula.</h3>

4 0

3 years ago

Read 2 more answers

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 11 m/s. The ball's height h (in meters) af

bonufazy [111]

Answer:

$t=0.64$ and $t=1.56$ seconds

Step-by-step explanation:

$h=1+11t-5t^2\\\\6=1+11t-5t^2\\\\0=-5+11t-5t^2\\\\0=-5t^2+11t-5\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-11\pm\sqrt{11^2-4(-5)(-5)}}{2(-5)}\\\\t=\frac{-11\pm\sqrt{121-100}}{-10}\\ \\t=\frac{-11\pm\sqrt{21}}{-10}\\\\t=\frac{11}{10}\pm\frac{\sqrt{21}}{10}\\ \\t_1\approx0.64\\\\t_2\approx1.56$