Answer:
![-7y](https://tex.z-dn.net/?f=-7y)
Step-by-step explanation:
Our equation is:
![\left(1x-5y\right)-1\left(x+2y\right)](https://tex.z-dn.net/?f=%5Cleft%281x-5y%5Cright%29-1%5Cleft%28x%2B2y%5Cright%29)
First we dritribute
Now we have, ![x-5y-x-2y](https://tex.z-dn.net/?f=x-5y-x-2y)
light terms
and we get ![-7y](https://tex.z-dn.net/?f=-7y)
Commutative Property of Multiplication
It’s the second one! I’m 100% sure lol it’s easy
Answer:
1. 1
2. 10
3. 12
Step-by-step explanation:
Answer:
<h2>After two and a half years, there would be 210 volunteers.</h2>
Step-by-step explanation:
Givens
- Each month there are added 5 people.
- The first month there are 125 volunteers.
These problem models a arithmetic sequence, where the difference is 5 and the first term is 125.
Notice that 2 and a half year are equivalent to 18 months. That means we need to find the 18th term,
A arithmetic sequence is defined as
![a_{n}=a_{1}+(n-1)d](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7B1%7D%2B%28n-1%29d)
Where
,
and
.
![a_{18}=125+(18-1)5=125+(17)5=125+85=210](https://tex.z-dn.net/?f=a_%7B18%7D%3D125%2B%2818-1%295%3D125%2B%2817%295%3D125%2B85%3D210)
Therefore, after two and a half years, there would be 210 volunteers.