First, multiply 1/4 by x+3 ⇒(1/4x+3/4). Next, multiply 3 by 1+x ⇒(3+3x). The equation should now look like this: 1/4x+3/4-4x≤3+3x. The next thing you have to do is get all of the x's on one side of the symbol. Subtract 1/4x from both sides, and the equation then looks like this: 3/4-4x≤3+2 3/4x. Add the -4x to both sides, and the equation should look like this: 3/4≤3+6 3/4x. Next, you have to move the 3 to the left side. To do that, subtract it from both sides. The equation then look like this: -2 1/4≤6 3/4x. Then, to get the x alone, you need to divide the coefficient (6 3/4) by -2 1/4, which equals -1/3 or -0.3 repeating. So, -1/3≤x
Answer:
To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
please mark me brainliest :)
I believe the number of terms in the sequence would be represented by the value on top of the sigma sign, which is 8. There would be 8 terms.
A=(pg) over 2 = four times thirty over two equals 60
Answer:
Its option A
Step-by-step explanation:
P=2l+2w
P=2(l+w)
P/2=l+w
P/2-l=w
(P-2l)/2=w
