Which describes the standard deviation?

Mathematics

2 answers:

max2010maxim [7]4 years ago

6 0

It is a form of measurement of the average difference between sample values and the sample mean.

aleksandrvk [35]4 years ago

3 0

Step-by-step explanation:

standard deviation is used to measure risks involved in an investment instrument. Standard deviation provides investors a mathematical basis for decisions to be made regarding their investment in financial market. Standard Deviation is a common term used in deals involving stocks, mutual funds, ETFs and others. Standard Deviation is also known as volatility. It gives a sense of how dispersed the data in a sample is from the mean.

I hope I answered correctly :)

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One - eighth of 7.92 x 10^10

liraira [26]

The answer is 9900000000 (thats 8 zeros) What you do is you find 10^10 which is 10000000000 (ten zeros) and multiply that by 7.92 to get 79200000000 then you just multiply it by 1/8 to get the answer.

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3 years ago

Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What

777dan777 [17]

Answer:

B) $\frac{3}{4}$ x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

= 40 units

Dilating KMPT by a scale factor of $\frac{3}{4}$ would create K'M'P'T' of dimensions; $\frac{3}{4}$ × 12 units by $\frac{3}{4}$ × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

= 2(9 + 6)

= 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be $\frac{3}{4}$ × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

perimeter of K'M'P'T' = $\frac{3}{4}$ * x units

= $\frac{3}{4}$ x units

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3 years ago

What is the perimeter of a rectangular garden with a width of 24 feet and a diagonal of 40 feet?

elena55 [62]

Drawing it out, as seen, using the Pythagorean theorem we get that w^2+l^2 (with w=width and l=length)=diagonal^2=24^2+l^2=40^2. Subtracting 24^2 from both sides, we get 40^2-24^2=l^2=1024. Square rooting both sides, we get l=32. Since the perimeter is 2w+2l, we get 32*2+24*2=64+48=112