The sum of 1/6 and 1/4 is ______

Roger wants to carpet a rectangular room with length of 8 3/4 feet and a width of 9 1/3 feet. If he has 85 square feet of carpet

Dima020 [189]

Answer:

12.66 $ft^2$

Step-by-step explanation:

Given the dimensions of the room are $8\frac{3}{4}$ = $\frac{31}{4}$ and $9\frac{1}{3}$ = $\frac{28}{3}$ .

The area of the room = $length*width$

Area= $\frac{31}{4} *\frac{28}{3}$

Area=72.33 $ft^2$

The area of the carpet=85 $ft^2$

The area of carpet left= Total area of carpet - the area of the room

The area of carpet left= 85-72.33=12.66 $ft^2$

7 0

3 years ago

Find the area<br><br> A: 54.94 cm<br> B: 40.59 cm<br> C: 33.165 cm<br> D: 27.47 cm

aleksandrvk [35]

D: 27.47 cm. A=b×h÷2

6.7×8.2=54.94
54.94÷2=27.47 cm

hey what can I say except your welcome.

8 0

3 years ago

Read 2 more answers

some students at a high school created a new school flag in the shape of an isosceles triangle points X and Y are located so tha

djyliett [7]

Answer:

180/7

Step-by-step explanation:

Comment if you want it, but it's very long.

3 0

2 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

Which expressions are completely factored?

amm1812

The only expressions that are correctly factored are;

A) 16a⁵ - 20a³ = 4a³(4a² - 5)

B) 24a⁴ + 18 = 6(4a⁴ + 3)

C) 12a³ + 8a = 4a(3a² + 2)

D) 30a⁶ - 24a² = 3a²(10a⁴ - 8)

<h3>How to factorize equations?</h3>

1) 16a⁵ - 20a³

To factorize this, we will have to get out the common factor first. The common factor is 4a³. Thus, we now have;

4a³(4a² - 5)

2) 24a⁴ + 18

To factorize this, we will have to get out the common factor first. The common factor is 6. Thus, we now have;

6(4a⁴ + 3)

3) 12a³ + 8a

To factorize this, we will have to get out the common factor first. The common factor is 4a. Thus, we now have;

4a(3a² + 2)

4) 30a⁶ - 24a²

To factorize this, we will have to get out the common factor first. The common factor is 3a². Thus, we now have;

3a²(10a⁴ - 8)

Read more about factorization of equations at; brainly.com/question/723406

#SPJ1

6 0

2 years ago

The sum of 1/6 and 1/4 is _______