Since <em>f(x)</em> is continuous, so is <em>h(x)</em>.
Also, since <em>f</em> (3) = 4 and <em>f</em> (5) = 2, we have
<em>h</em> (3) = <em>f</em> (3) + 2•3 = 4 + 6 = 10
<em>h</em> (5) = <em>f</em> (5) + 2•5 = 2 + 10 = 12
It follows from the intermediate value theorem that there is some <em>t</em> between 3 and 5 such that <em>h(t)</em> is between 10 and 12, and namely there is some <em>t</em> for which <em>h(t)</em> = 11.
Answer:
use what
Step-by-step explanation:
-15x - 3y = 3
-15x - 3(5x-1) = 3 [input y]
-15x - 15x - 3 = 3 [distribute 3 over 5x and -1]
-30x - 3 = 3 [combine like terms]
-30x = 6 [add 3 to eliminate the negative]
x =

[divide by -30 to get x alone]
x =

[reduce the fraction]
Hopefully this is helpful enough to get you to your answer
Answer:
The total surface area of this square pyramid is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
----> the length side of the square base
----> the height of the triangular faces
substitute the values
![SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D%3D297%5C%20mm%5E%7B2%7D)