What is the area of this rhombus? Pls answer fast
2 answers:
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Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
<u>Answer:</u> The value of x will be 2.
<u>Step-by-step explanation:</u>
To calculate the value of 'x' or solve for x, we need to isolate x from 8.
In the equation, 8 is in addition with 'x' so for isolating it, we need to apply the reverse operation of addition.
Reverse operation of addition is subtraction.
We need to subtract 8 from both sides of the equation, we get:
By doing this, we get the value of 'x' as 2.
Error done by Alice was that she added 8 and it did not led to the isolation of 'x'.