To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer:
4
Step-by-step explanation:
rise/run = slope
As it goes to the left or adds by one, it goes up by 4
4/1
Y2-y1/x2-x1= -47-(-7)/-19-(-9)= 4
Answer:
6 i think
Step-by-step explanation:
