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prohojiy [21]
3 years ago
10

PLEASE HELP! ( no random links )

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

This is not a statistical question

Step-by-step explanation:

A statistical question is a question the gathers varying data

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How many numbers between 111 and 100100100 (inclusive) are divisible by 333 and 101010?
EleoNora [17]
If the numbers that we are checking divisibility for are between 1-100, there are 3 numbers.

30, 60, and 90 are all divisible by both 3 and 10 because both 3 and 10 are factors of these 3 numbers.
5 0
2 years ago
Read 2 more answers
If x varies directly as y, and x=12 when y=3, find x when y=7
Stella [2.4K]

Answer:

28

Step-by-step explanation:

x=12 and y=3

x=4 and y =1

x=28 and y=7

3 0
3 years ago
Read 2 more answers
Amelia and Jayden work at a furniture store. Amelia is paid $185 per week plus 9.5% of her total sales in dollars, xx, which can
almond37 [142]

Answer:

The weekly sales must be $12,600

Step-by-step explanation:

if their pay is the same, the equations have to be equal

amelia = jayden

185 +.095x = 311 +.085x

subtract  .085x from each side

185 +.095x-.085x = 311 +.085x-.085x

185+.01x = 311

subtract 185 from each side

185-185+.01x = 311-185

.01x = 126

divide by .01

.01x/.01 = 126/.01

x = 12600

7 0
3 years ago
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
A) The sum of −3x+5 and 7−4x is subtracted from 5x+17.
AlekseyPX
A. -3x+5+7-4x 
  -3x-4x+5+7 
-7x+12 

-7x+12-5x+17 
-7x-5x+12+17
-12x+29

B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
  -11x-11

8 0
3 years ago
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