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svetoff [14.1K]
3 years ago
8

Anyone know this and if do pls help

Mathematics
2 answers:
Margaret [11]3 years ago
7 0

70% of the trip length, t, is 35 miles. Find t:

0.70t = 35. Dividing both sides by 0.70, we get:

35

t = ----------- = 50

0.70

The total trip length is 50 miles.

ivanzaharov [21]3 years ago
6 0
50is the correct answer
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A cereal manufacturer produces cereal in boxes having a labeled weight of 15.7 ounces. Suppose that a random sample of 31 boxes
taurus [48]

Answer:

t=\frac{16.14-15.7}{\frac{1.18}{\sqrt{31}}}=2.076    

p_v =P(t_{(30)}>2.076)=0.0233  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean for the weigths of cereal boxes is higher than 15.7 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=16.14 represent the sample mean

s=1.18 represent the sample standard deviation

n=31 sample size  

\mu_o =15.7 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 15.7 or no, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15.7  

Alternative hypothesis:\mu > 15.7  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{16.14-15.7}{\frac{1.18}{\sqrt{31}}}=2.076    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=31-1=30  

Since is a one side test the p value would be:  

p_v =P(t_{(30)}>2.076)=0.0233  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence toreject the null hypothesis, and we can conclude that the true mean for the weigths of cereal boxes is higher than 15.7 at 5% of signficance.  

4 0
3 years ago
greg bought a blanket for $33.34, a flag for $12.25, and a glove for $12.75. He paid $40 and the rest he borrowed from his frien
Lelu [443]

Answer:

He borrowed 16.68

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help needed ASAP!!!!!!!
alekssr [168]

Answer: 4 is 110 degrees  and 3 and 1 is 70 degrees.

Step-by-step explanation: 4 is equal to 2 so 4 is 110 degrees 4

110 x 2 = 220  360 - 220 = 140/2 = 70 so 3 and 1 = 70 degrees

8 0
2 years ago
Read 2 more answers
Rod is paid an overtime rate of $25 per hour after he earns his basic wage of $600 per week. Write an equation in slope- interce
SpyIntel [72]
P = 25h + 600. 

This is because even if he works no overtime, he still gets his 600. 
5 0
3 years ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
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