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trasher [3.6K]
2 years ago
13

Compared to the tone of Passage 2, the tone of

Mathematics
1 answer:
harkovskaia [24]2 years ago
4 0

The correct answer is option e) tempered.

Compared to the tone of Passage 2, the tone of Passage 1 is more tempered.

Passage 1 discusses recycling as a socio-cultural phenomena, whereas passage 2 is a recycling critique.

Therefore, the tone of passage 1 is a little more upbeat than that of passage 2.

As a result, we may determine that tempered is the most appropriate tone for this passage 1.

Learn more about ("Angel") Deverell

brainly.com/question/24852631

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A pet store sells mice, reptiles, and birds.
kirill115 [55]

Answer:

The answer is C.

8 0
3 years ago
4p = 14.4<br> What is the value of p?<br> A. 3.6<br> B 3.8<br> C.10.4<br> D.57.6
4vir4ik [10]
The answer to your question is A.

answer: 3.6
6 0
2 years ago
Read 2 more answers
Select the correct answer from each drop-down menu. y = x2 + 2x − 1 y − 3x = 5 The pair of points representing the solution set
katen-ka-za [31]

ANSWER

(-2,-1)

(3,14)

EXPLANATION

The given system is

y =  {x}^{2}  + 2x - 1

y - 3x = 5

or

y = 3x + 5

Equate both of them:

{x}^{2}  + 2x - 1 = 3x + 5

This implies that,

{x}^{2}   - x - 6 = 0

(x - 3)(x + 2) = 0

x=-2 or x=3

When x=-2, y=y=3(-2)+5=-1

(-2,-1) is a solution.

When x=3 , y=3(3)+5=14

(3,14) is also a solution.

7 0
3 years ago
Evaluate xtosecond power divided by 12 minus x for x=6
jenyasd209 [6]

Answer: 3


Step-by-step explanation:

Given: x^2/12

Now, substitute. 6^2/12

36/12

3

4 0
3 years ago
Read 2 more answers
When a certain drug is taken orally, the concentration of the drug in the patient's bloodstream after t minutes is given by
sineoko [7]
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins

The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
7 0
3 years ago
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