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iragen [17]
3 years ago
14

27

Mathematics
1 answer:
larisa [96]3 years ago
5 0

Answer:

The original nimber is 67.

Step-by-step explanation:

Let the two digits be x and y.

According to the question.

The sum of two digits of a two digit number is

x + y = 13

or, x = 13 - y

And, a two digit number can be written as

x × 10 + y

when the digits are reversed, the number can be written as

y × 10 + x

the original number increases by 9. i.e.

y x 10 + x = x × 10 + y + 9

Replacing value of x by 13 - y,

y × 10 + 13 - y = 10(13 - y) + y + 9

10y + 13 - y = 130 - 10y + y + 9

9y + 13 = 139 - 9y

18y = 139 - 13

18y = 126

y = 126/18

y = 7

So, x = 13 - y

= 13 - 7

= 6

The original number is x × 10 + y = 6 x 10 + 7 = 67.

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Your parents have a realized income of $1,046.78/every 2 weeks. How much should the monthly housing expense budget be to stay wi
IgorLugansk [536]

Answer with explanation:

Income earned by my parents in every two weeks = $ 1046.78

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              =\frac{1046.78}{14}\\\\74.77

Income of my parents after a month, if there are 30 days in a month = $74.77 × 30= $ 2243.10

We, will use ,\frac{28}{36} rule here , which states that , 28% of monthly income of my parents, should be used for  monthly housing expenses ,and 36% of gross monthly income should be used for debt purposes.

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8 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

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(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
3 years ago
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