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iragen [17]
2 years ago
14

27

Mathematics
1 answer:
larisa [96]2 years ago
5 0

Answer:

The original nimber is 67.

Step-by-step explanation:

Let the two digits be x and y.

According to the question.

The sum of two digits of a two digit number is

x + y = 13

or, x = 13 - y

And, a two digit number can be written as

x × 10 + y

when the digits are reversed, the number can be written as

y × 10 + x

the original number increases by 9. i.e.

y x 10 + x = x × 10 + y + 9

Replacing value of x by 13 - y,

y × 10 + 13 - y = 10(13 - y) + y + 9

10y + 13 - y = 130 - 10y + y + 9

9y + 13 = 139 - 9y

18y = 139 - 13

18y = 126

y = 126/18

y = 7

So, x = 13 - y

= 13 - 7

= 6

The original number is x × 10 + y = 6 x 10 + 7 = 67.

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Which relation is a function?
yKpoI14uk [10]

Answer:

C

Step-by-step explanation:

if you don't have from same x different outcomes is a function

think that x is a day you count votes, you can not get for the same day different y number of votes ( something is fishy then)

A. not a function because (6, -3) and (6, 3)

B. not  a function because (4,7) and (4,2)

C. is a function

D. not a function because (2, -1) (2,1) (2,3)

4 0
3 years ago
A square pyramid has a height of 12 units and a volume of 256 units3. If a square prism has the same the base area and volume as
Juliette [100K]

Answer:

4 units

Step-by-step explanation:

The volume of a square pyramid is (a²)*h/3

256=a²*12/3

256=a²*4

256/4=a²

64=a²

a=8

Now we know that the square is 8 by 8.

The volume of a square prism is a²h

256=64h

256/64=h

h=4

Also, a square pyramid is 1/3 the volume of a square prism.

12÷3=4

3 0
3 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
find the height of the cylinder below whose volume is approximately 1000 cubic inches use 3.14 for pi round your answer to the n
gtnhenbr [62]

Answer:

h = 1000 / (3.14)(r²)

Step-by-step explanation:

Given in the question,

volume of cylinder = 1000 inches³

Formula to use

V = πr²h

where V = volume

           π = 3.14

           r = radius

           h = height

1000 = (3.14)(r²)(h)

h = 1000 / (3.14)(r²)

               

5 0
3 years ago
Simplify 2(12-18\3+4)
Goshia [24]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

Simplify

2(12 -  \frac{18}{3}  + 4)

\huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}

ATQ->

2(12 - ( \frac{ \cancel{18}^{ \:  \:  \: 6} }{3} ) + 4 \\ 2(12 - 6 + 4) \\ 2(16 - 6) \\ 2(10) \\ 20 \:  \: is \: your \: ans

4 0
3 years ago
Read 2 more answers
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