<span>A
and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1,
we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix)
and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>
Answer:
it the second one
Step-by-step explanation:
i just took the test
You add all the numbers & divide it by how many numbers 8 +9+9+9+10+10
Answer:
y = -1/11 + 5
Step-by-step explanation:
1x + 11y = 55
-1x -1x
11y = -1x + 55
/11 /11
y = -1/11 + 5
Hope this helps!