Given parameters:
Actual length = 260m
Drawing length = 286mm
Unknown:
Scale used = ?
Solution:
A scale compares drawing length to ground distance;
To find the scale,
Express the two quantities in the same unit;
actual length = 260 x 10⁻³m = 0.26mm
Now;
drawing length : actual length
286mm : 260 x 10⁻³mm
divide by 286;
1mm on drawing : 9 x 10⁻⁴mm on map
or;
1mm on drawing is 0.9m on ground
Answer:
The percentages are 267% and 400% respectively.
Step-by-step explanation:
To find the answers of these, you need to divide the second number by the first. This will give you the percentage.
2/3 ÷ 1/4 = 8/3 = 2.67 = 267%
You can do the same for the second one.
2/3 ÷ 1/6 = 12/3 = 4 = 400%
Answer:
C and G
Step-by-step explanation:
(x^2+4)^2+32=12x^2+48 is written as 
.
We can simplify the expression using the term a by replacing x^2 + 4 with a.
This factors into (a-4)(a-8). Solve by setting each factor equal to 0 and solve for a.
a-4 = 0 a=4
a-8=0 a=8
So if Bill runs 10 miles in those 4 days then we need to find out Val's.
2 and 3/5. Well, we already know 2*4=8
so 0.6 (which is 3/5) multiplied by 4 is 2.4.
8+2.4=10.4
So here are the results for the distance covered in 4 days :
Val = 10.4 miles
Bill = 10 miles
Therefore, I think Val covers the most distance in 4 days.
Hope I helped :)
Can u explain it a little more clearly...
