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2 years ago

Can someone help, please?

Mathematics

1 answer:

Kipish [7]2 years ago

5 0

I think the answer is c

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10 points please help

jolli1 [7]

6* 8.4
7* 3.5
8* -6
9* 10.899
10* 11.1
11* 2.4
12* 0.06
13* 2.2
14* 15.2
15* 11.7
16* -3.4

explanation: Sorry i couldn’t finish and i hope these are correct! I’m not that good at math but good luck

4 0

3 years ago

Please help me giving brainliest

Gemiola [76]

Answer:

42cm^2

3x2=6x7=42

Step-by-step explanation:

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

7 0

2 years ago

What is 7,390.7 divided by 0.874 ?

Alinara [238K]

About 8,456.17849
Rounded: 8,456.18

3 0

3 years ago

Can someone explain how to get the answer?

Murljashka [212]

A = ((6 + 7 + 6) . 8)/2
A = 19 . 4
A = 76

6 0

3 years ago

Read 2 more answers