Figure 1 and figure 2 are show on the coordinate plane below.

slader How many partitions of the set {1, 2, 3, . . . , 100} are there such that there are exactly three parts and elements 1, 2

My name is Ann [436]

Answer:

$3^{97}$ partitions.

Step-by-step explanation:

As we know if we have x number of elements we can arrange them in x! ways.

here we have 100 elements so we can arrange them in 100! ways.

Now if we have exactly three parts and 1,2 and 3 are in different parts then let consider 1 goes to part 1, 2 goes to part 2, and 3 goes to part 3. For the remaining 97 elements, we have three options for each element, thus we can arrange the remaining 97 elements in $3^{97}$ ways/partitions.

each of these partition will contain only three elements.

7 0

3 years ago

How to classify the quadrilateral in as many ways as possible

madam [21]

Rhombus, Parallelogram, Kite, Rectangle, Square, Trapezoid, Isosceles Trapezoid

6 0

3 years ago

Which is a better buy? 5000 sqft of lawn food for $11.99 or 12500 sqft of lawn food for $19.99? Show proof.

xz_007 [3.2K]

12500 cause 5000 goes into 12500 twice and it would be 24$ for 10000 sqft and then another 6 so 30$ cause 2500 is half of 5000

3 0

3 years ago

Find the value of Z please help

JulijaS [17]

I think it is 1 because it is smaller than 1.5 so it would have to be 1

4 0

3 years ago

Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa

blagie [28]

Answer:

$z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9$

$p_v =P(z>1.9)=0.0287$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=12.95$ represent the sample mean

$\sigma=3$ represent the population standard deviation for the sample

$n=36$ sample size

$\mu_o =12$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:

Null hypothesis: $\mu \leq 12$

Alternative hypothesis: $\mu > 12$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9$

P-value

Since is a right tailed test the p value would be:

$p_v =P(z>1.9)=0.0287$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.

4 0

3 years ago

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