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MAVERICK [17]
2 years ago
14

Benson is shopping for shampoo. His favorite brand comes in 5 different sizes which size is the best deal

Mathematics
1 answer:
aleksandrvk [35]2 years ago
7 0
What are the 5 different sizes? Can you be more specific?
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.....................
Norma-Jean [14]

Answer:

3) 5 centimeters

Step-by-step explanation:

Plug 3 and 4 into the formula for the Pythagorean Theorem. You get 5.

6 0
2 years ago
A moving sidewalk takes zoo visitors up a hill. The
irina [24]

Answer:

x = 185.458 ft

Step-by-step explanation:

When we draw a picture, we are able to see that we need to use sin∅ to solve this problem:

sin15° = 48/x

xsin15° = 48

x = 48/sin14°

7 0
3 years ago
Please answer this question correctly. Need help ASAP.!
Tomtit [17]

Answer:

approximation is often useful when it is not a very good one

3 0
2 years ago
Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
Given that f(x)=6x+2 and g(x)= 2x+4/5 solve for g(f(1))
kolbaska11 [484]

Note that f(1) = 6(1)+2 = 8.  Next, evaluate g(x) at x=8:  g(f(1)) = g(8) = 2(8) + 4/5, or 16 4/5.

3 0
3 years ago
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