Answer:
x = 39
Step-by-step explanation:
there is a theorem that states that the midsegment in a trapezoid is equal to the sum of the bases divided by two
so, (36 + 42)/2 = x
36 + 42 = 78
78/2 = 39
A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:

Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1





We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height
Put height value in equation 1







Therefore ,time interval of camera film him is 
Answer:
si =25%*p
rate =term=t
from si= ptr/100
term = rate = 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
both represent the same line .
Hence it has infinite solutions as there are infinite points on aline.
Y = - 25.1
I hope this helps.
I hope you pass! :D