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Talja [164]
3 years ago
13

Steve is looking up at Godzilla with an angle of elevation of 49 degrees. If Steve is 400 feet away, how tall is Godzilla to the

nearest foot?
Mathematics
2 answers:
tatiyna3 years ago
6 0

9514 1404 393

Answer:

  460 feet

Step-by-step explanation:

The tangent relates the measures to the angle:

  tan(angle of elevation) = (Godzilla height)/(distance away)

  tan(49°) = (Godzilla height)/(400 ft)

  Godzilla height = (400 ft)(tan(49°)) ≈ 460 ft

Godzilla is 460 feet tall.

miv72 [106K]3 years ago
5 0

Answer:

godzilla is 393 foot tall

Step-by-step explanation:

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Type a digit that makes this statement true.
Aneli [31]

Answer:

1, 3, 5, 7, or 9

Step-by-step explanation:

For 14, 213, 1__2 to be divisible by 4, the last two digits must be divisible by 4.

Using this knowledge, any odd single digit number would make the statement true.

14, 213, 112 ÷ 4 = 3, 553, 278

14, 213, 132 ÷ 4 = 3, 553, 283

14, 213, 152 ÷ 4 = 3, 553, 288

14, 213, 172 ÷ 4 = 3, 553, 293

14, 213, 192 ÷ 4 = 3, 553, 298

Hope this helped!

3 0
2 years ago
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Michael's bill at a restaurant was $46.32. He wants to leave a 17% tip. What will the new total be,including the tip?
Novosadov [1.4K]
$7.87+$46.32=$54.19.  If you multiply 46.32 by 0.17, 17%, it is 7.87 so you just add that to the original bill, 46.32
5 0
3 years ago
Henrietta is planting a new flower garden she must have yellow and red rose bushes let X represent the number of yellow rose bus
salantis [7]

Answer:

x \geq 4y

7.50x+4.75y\leq 125

x > 0

y > 0

Step-by-step explanation:

Let

x -----> the number of yellow rose bushes

y -----> the number of red rose bushes

we know that

At least means "greater than or equal to"

x \geq 4y ----> inequality A

7.50x+4.75y\leq 125 -----> inequality B

additionally

The number of roses cannot be a negative number

so

x > 0 ----> inequality C

y > 0 ----> inequality D

therefore

The restraints are

x \geq 4y

7.50x+4.75y\leq 125

x > 0

y > 0

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3 years ago
AP Calculus Help Please!
ivanzaharov [21]
4. By the fundamental theorem of calculus,

\displaystyle\frac{\mathrm dg(x)}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\int_{-2}^xf(t)\,\mathrm dt=f(x)

g(x) is increasing on those intervals where g'(x)=\dfrac{\mathrm dg(x)}{\mathrm dx}>0. So you have

g'(x)=f(x)=\begin{cases}3&\text{for }-3\le x

which is clearly positive for x\in[-3,0), and in the second interval you have

-x+3>0\implies x

Together, this means g'(x)>0 for all x\in[-3,3).

5. When 0\le x\le6, f(x) reduces to -x+3, so you have

g(x)=\displaystyle\int_{-2}^xf(t)\,\mathrm dt=\int_{-2}^03\,\mathrm dt+\int_0^x(-t+3)\,\mathrm dt
g(x)=6+\left(3t-\dfrac12t^2\right)\bigg|_{t=0}^{t=x}
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