Answer: Be Te Dubs meaning BTW Go To TigerAlgebra.com for questions like yours its really great
Step-by-step explanation:
|3x+6|<12
One solution was found :
-6 < x < 2
Absolute Value Inequality entered :
|3x+6|<12
Step by step solution :
Step 1 :
Rearrange this Absolute Value Inequality
Absolute value inequalitiy entered
|3x+6| < 12
Step 2 :
Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |3x+6|
For the Negative case we'll use -(3x+6)
For the Positive case we'll use (3x+6)
Step 3 :
Solve the Negative Case
-(3x+6) < 12
Multiply
-3x-6 < 12
Rearrange and Add up
-3x < 18
Divide both sides by 3
-x < 6
Multiply both sides by (-1)
Remember to flip the inequality sign
x > -6
Which is the solution for the Negative Case
Step 4 :
Solve the Positive Case
(3x+6) < 12
Rearrange and Add up
3x < 6
Divide both sides by 3
x < 2
Which is the solution for the Positive Case
Step 5 :
Wrap up the solution
-6 < x < 2
Solution in Interval Notation
(-6,2)
Solution on the Number Line
One solution was found :
-6 < x < 2
Answer:
d = 2* sqrt(a^2 + b^2)
Step-by-step explanation:
Interesting question. You should begin by noting that 0 is not the answer although it looks like it should be.
P = (a,b)
Q= (-a,-b)
x1 = a
x2 = - a
y1 = b
y2 = - b
d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
d = sqrt( (-a - a)^2 + (-b - b)^2 )
d = sqrt ( -2a)^2 + - (2b)^2 )
d = sqrt(4a^2 + 4b^3)
d = 2* sqrt(a^2 + b^2)
J'(4, 0)
F'(5, 2)
N'(5, -1)
Answer:
1/9 of 11
Step-by-step explanation:
Firstly find sp and then calculate
