So how to solve x for 8/15+x=21/25 ?

Rotate the rectangle 90∘ clockwise about the cross

netineya [11]

Answer:

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Step-by-step explanation:

The rectangle is rotated 90 degrees clockwise about the cross.

8 0

2 years ago

10 A solid metallic cylinder of radius 14 cm and

vodomira [7]

Answer:

72 spheres are formed

Step-by-step explanation:

We start by calculating the volume of the metallic cylinder

Mathematically, we have this as;

V = pi * r^2 * h

V = pi * 21 * 14^2

V = 4116 π cm^3

The volume of each small sphere is;

V = 4/3 * pi * r^3

= 4/3 * π * 7/2^3 = 57.167 π cm^3

To get the number of small spheres, we simply divide the volumes

That will be 4116 pi / 57.167 pi = 72

4 0

2 years ago

Mary and Lamar establish a tutoring service at a local mall. They tutor college students in math and English. They charge $40 pe

Hatshy [7]

The profit is $3300 for the month of January.

Step-by-step explanation:

Per hour charge = $40

Total number of tutoring hours = 200

Rent of space = $4000

Electricity = $325

Advertising = $375

Total expenses = 4000+325+375 = $4700

Profit = $40(number of hours) - (expenses)

$Profit=\$40(200)-4700\\Profit=\$8000-4700\\Profit=\$3300$

The profit is $3300 for the month of January.

Keywords: profit, addition

Learn more about addition at:

#LearnwithBrainly

7 0

3 years ago

What is the solution set of the equation x2 + 3x - 4 = 6?

mojhsa [17]

The answer is A. (-5,2) . also i suggest you using photomath if you have a trouble with a problem it will give you the answer and the steps to solve

3 0

3 years ago

Estimate the indicated probability by using the normal approximation as an approximation to the binomial distribution. (PROBLEMS

S_A_V [24]

Answer:

4

$P(X \ge 219 ) = 0.093$

5

$P(X \ge 219 ) = 0.1038$

Step-by-step explanation:

From the question we are told that

The percentage of hair dryers that are defective is p=2% $= 0.02$

The sample size is $n =10000$

The random number is x = 219

The mean of this data set is evaluated as

$\mu = n* p$

substituting values

$\mu = 10000 * 0.02$

$\mu =200$

The standard deviation is evaluated as

$\sigma = \sqrt{[\mu (1 -p)]}$

substituting values

$\sigma = \sqrt{[200 (1 -0.02)]}$

$\sigma = 14$

Since it is a one tail test the degree of freedom is

df = 0.5

So

$x_l = x- 0.5$

$x = 219 - 0.5$

$x = 218.05$

Now applying normal approximation

$P(X \ge 219 ) = P(z > \frac{x - \mu}{\sigma} )$

substituting values

$P(X \ge 219 ) = P(z > \frac{218.5 - 200}{14} )$

$P(X \ge 219 ) = P(z > 1.32} )$

From the z-table

$P(X \ge 219 ) = 0.093$

Considering Question 5

The random number is x = 90

The mean is $\mu = n * p$

Where n = 100

and p = 0.85

So

$\mu = 0.85 *100$

$\mu = 85$

The standard deviation is evaluated as

$\sigma = \sqrt{[\mu (1 -p)]}$

substituting values

$\sigma = \sqrt{[85 (1 -0.85)]}$

$\sigma = 3.5707$

Since it is a one tail test the degree of freedom is

df = 0.5

Now applying normal approximation

$P(X \ge 90 ) = P(z > \frac{x - \mu}{\sigma} )$

substituting values

$P(X \ge 219 ) = P(z > \frac{89.5 - 85}{3.5707} )$

$P(X \ge 219 ) = P(z > 1.2603} )$

From the z-table

$P(X \ge 219 ) = 0.1038$

8 0

3 years ago