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denis23 [38]
3 years ago
7

Belinda went biking on Saturday and rode for 6 4/5 miles. On Sunday she rode for 2/3 of the distance she rode on Saturday. Write

and solve an equation that will help you figure out how far Belinda rode on Sunday. Explain the steps you took to solve the problem.
(solve step by step)
Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

68/15 miles

Step-by-step explanation:

Miles she rode on Saturday = (6x5+4) / 5 = 34/5 miles

Miles she rode on Sunday = 34/5 x 2/3 = 68/15 miles --As it is stated that she rode 2/3 of the distance of Saturday's, so simply multiple it by 2/3

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Answer:

see below

Step-by-step explanation:

2.5 = 2 5/10 = 250%

40% = .40 = 40/100 = 4/10 =2/5

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1/4 = 25/100 = 25%

4% = 4/100 = .04

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daser333 [38]

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3 years ago
What is the missing output value in the function table below
elena-s [515]

Answer:

2

Step-by-step explanation:

It makes sense because it goes down one by one in both the input and output values

8 0
3 years ago
1) Find an equation of the line that passes through thr pair of points (-5,-9) and (2,-7).
Yuki888 [10]
1: Assuming this line is linear, the first thing to do is find the slope. 
The slope formula is m=\frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }, so in this case, it is m=\frac{ (-7) - (-9) }{ 2 - (-5) }, which comes to \frac{2}{7}. Then, use your slope and one of the points given to write the point-slope formula of the linear equation, and then written in standard form:
y=\frac{2}{7}x-\frac{53}{7}.

2. Use the same process as in question 1 to find:
y=-7x+11


8 0
3 years ago
22. Mona is in her garden jumping on stones (as shown below).
iris [78.8K]

\large\green{\sf\boxed{Given:-}}

<u>Mona starts from 68th stone</u>

<u>She jumps</u><u> </u><u>23</u><u> </u><u>stones</u><u> </u><u>ahead</u><u> </u>

<u>Then</u><u> </u><u>she</u><u> </u><u>jumps</u><u> </u><u>28</u><u> </u><u>stones</u><u> </u><u>back</u>

\large\red{\sf\boxed{To \:find:-}}

<em>Her final position=?</em>

\large{|\underline{\mathtt{\red{S}\blue{o}\orange{l}\pink{u}\blue{t}\purple{i}\green{o}\red{n}\blue{:}\orange{-}}}}

  • Add 23 in 68 [Given]

\begin{gathered}\\ \sf\longmapsto 68+23=91\end{gathered}

  • Subtract 28 from 91

\begin{gathered}\\ \sf\longmapsto 91-28=Her\:final\:position\end{gathered}

\begin{gathered}\\ \sf\longmapsto =63\end{gathered}

  • To find how much stones she is ahead or back we will Subtract 63 from 68 which was her initial position.

\begin{gathered}\\ \sf\longmapsto 68-63=5\end{gathered}

So, Mona will be <em><u>5</u></em><em><u> </u></em><em><u>stones</u></em><em><u> </u></em><em><u>behind</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>starting</u></em><em><u> </u></em><em><u>stone</u></em><em><u>.</u></em>

☯️Hence, Option C is correct

7 0
3 years ago
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