Answer:
Step-by-step explanation:
if you are going in a negative direction or by a decimal you are contracting, so the image would get smaller. If you are going in a positive direction(has to be a whole number as well) you have an expansion.
Answer:
2nd option is correct as it has represented all the terms of the expression.
Answer:
Solution given:
For 1st
x²=71
For x=±
and
For 2nd
x³=71
For x=±![\sqrt[3]{71}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B71%7D)
So answer is:
In first row
<u>Solution to x²=71</u>
In second row
<u>Solution to </u><u>x³</u><u>=71</u>
In third row
<u>neither</u>
In forth row
<u>Solution to x³=71</u>
Answer:
J + 9 = 63
Jackson = 54 inches
Step-by-step explanation:
Using the variable 'J' for the height of Jackson, we know that Elliott is Jackson's height, plus an additional 9 inches. Since Elliott is 64 inches tall in total, we can add Jackson's height plus 9 to get Elliot's height:
Jackson's height + 9 inches = Elliot's height
J + 9 = 63
Subtract '9' from both sides: J + 9 - 9 = 63 - 9 or J = 54
So, Jackson is 54 inches tall.
The surface in medium is connected to both y and e