All categories

3 years ago

FIND THE SLOPE OF THE LINe -2/1 -1/2 1/2 2/1

Mathematics

2 answers:

ahrayia [7]3 years ago

4 0

Answer:

7ygfce

Step-by-step explanation:

Vika [28.1K]3 years ago

3 0

The answer is 1/2 !! start from the left point and do rise over run!!

You might be interested in

Simplify to create an equivalent expression. -k-(-8k+7)

const2013 [10]

Answer:

7k -7

Step-by-step explanation:

-k-(-8k+7)

Distribute the minus sign to all terms in the parentheses

-k--8k-7

Ad negative negative is a positive

-k + 8k -7

Combine like terms

7k -7

8 0

3 years ago

Can i have some help?? Please???????????????

Sergeeva-Olga [200]

the second is a negative slope due to the fact the line is going the the left and the ind variable is breakfast dep is performance

4 0

3 years ago

Find the generating function for the sequence 1,-2,4,-8, 16, ...

kirill [66]

Answer:

$a(x)=\dfrac{1}{1+2x}$

Step-by-step explanation:

The generating function a(x) produces a power series ...

$a(x)=a_0+a_1x+a_2x^2+a_3x^3+\dots$

where the coefficients are the elements of the given sequence.

We observe that the given sequence has the recurrence relation ...

$a_0=1;a_n=-2a_{n-1} \quad\text{for n $>$ 0}$

This can be rearranged to ...

$a_n+2a_{n-1}=0$

We can formulate this in terms of a(x) as follows, then solve for a(x).

$\sum\limits^{\infty}_{n=1} {a_{n}x^n} =a(x)-a_0 \quad\text{and}\\\\\sum\limits^{\infty}_{n=1} {2a_{n-1}x^n} =(2x)a(x) \quad\text{so}\\\\\sum\limits^{\infty}_{n=1} {(a_n+2a_{n-1})x^n}=0=a(x)-a_0+2xa(x)\\\\a(x)=\dfrac{a_0}{1+2x}=\dfrac{1}{1+2x}$

The generating function is ...

a(x) = 1/(1+2x)

3 0

3 years ago

Read 2 more answers

The mean of a set of credit scores is Mu = 690 and Sigma = 14. Which statement must be true about z694? z694 is within 1 standar

Kitty [74]

Answer:

I believe it's B

Step-by-step explanation:

hope this helps!

5 0

3 years ago

Read 2 more answers

The answer is 8 but how do you solve it<br><br> 6-2(3-4)

Neko [114]

Start with the parentheses

3 0

3 years ago

Read 2 more answers