Of course not.
If the line rises higher as it goes from left to right,
then its slope ( 'm' ) is positive.
If it sinks lower as it goes from left to right,
then its slope ( 'm' ) is negative.
A. Sugar And Brown Sugar (For Cookies)
B. No.
C 1/2 Cup (INGREDIENT) And 1/8 Cup (INGREDIENT)
We know that this is a parabola, as the equation is denoted by the x^2 term.
We can see that the symmetry is seen at the point -0.5, therefore making the axis of symmetry the vertical line -0.5.
The vertex is found in quadrant three. In other words, it will shift by a negative value both horizontally and vertically. The vertex is therefore (-0.5, -0.5).
We can verify this in the equations by using the formula (-b/2a) to find the vertex. The only quadratic equation that satisfies this is -2x^2 + 2x -1.
To sum it up, the answers are:
-2x^2 + 2x - 1.
AoS: x = -0.5
Vertex: (-0.5, -0.5).
X= 2/3
6x/x-6 - 4/x - 24 / x^2 - 6x = 0
6x^2 -4 (x-6)-24 / x(x-6) = 0
6x^2 -4x+ 24 -24/x(x-6) = 0
X(6x-4) / x(x-6)
6x-4/x-5 = 0
6x-4= 0
6x = 4 divide both sides by 6
X= 2/3
Alright...simple...showing all steps.. ;)
You have the equations...
2x+y=7
and
3x+5y=14
To be able to even solve for any of the variables...multiply the equations by...2...and..3...
2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28
Thus,
6x+3y=21
-
6x+10y=28
=========
-7y=-7
y=1
Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....
2x+(1)=7
2x+1=7
-1 -1
2x=6
x=3
Thus, the point of intersection for these two equations is (3,1)
