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3 years ago

3 x f(−4)−3 x g(−2)=

Mathematics

1 answer:

lukranit [14]3 years ago

7 0

Answer:

−12+6

Step-by-step explanation:

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Hey guys I’m giving away free points today

pentagon [3]

Answer:

yayyyy!!!

Step-by-step explanation:

thanks that's very generous

3 0

3 years ago

Read 2 more answers

Skye ran r laps today at soccer practice. Nadine ran five fewer laps than Skye. If Nadine ran eight laps at practice, which of t

jeka94

Answer: r - 5 = 8

Step-by-step explanation:

From the question, we are informed that Skye ran r laps today at soccer practice while Nadine ran five fewer laps than Skye.

If Nadine ran eight laps at practice, the equation that can be used to find how many laps Skye ran will be:

r - 5 = 8

This means Skye ran 13 laps

6 0

3 years ago

A construction worker measures the amount of cement in a cement truck every 5 minutes as it empties. The table shows the data Wh

Olin [163]

Answer:

Step-by-step explanation:

210 - 175 = 35

175 - 140 = 35

140 - 105 = 35

105 - 70 = 35

I hope this helps!

7 0

2 years ago

P(x) = x3 - 2x2 + 2x<br> What are the real and complex zeros of the equation

vesna_86 [32]

Given:

The polynomial is

$p(x)=x^3-2x^2+2x$

To find:

The real and complex zeros of the equation.

Solution:

We have,

$p(x)=x^3-2x^2+2x$

For zeros, p(x)=0.

$x^3-2x^2+2x=0$

$x(x^2-2x+2)=0$

$x=0\text{ and }x^2-2x+2=0$

The real value of x is 0. The equation $x^2-2x+2=0$ will give complex roots. Here, a=1, b=-2 and c=2.

Using quadratic formula, we get

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(1)(2)}}{2(1)}$

$x=\dfrac{2\pm \sqrt{4-8}}{2}$

$x=\dfrac{2\pm \sqrt{-4}}{2}$

On further simplification, we get

$x=\dfrac{2\pm \sqrt{-1}\sqrt{4}}{2}$

$x=\dfrac{2\pm 2i}{2}$

$x=\dfrac{2(1\pm i)}{2}$

$x=1\pm i$

Therefore, the real zero is 0 and the complex zeros are 1+i and 1-i.

5 0

2 years ago

In November, the rain in a certain valley tends to fall in storms of several days duration. The unconditional probability of rai

Mumz [18]

Answer:

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.

Step-by-step explanation:

Rain on November 1:

0.9 of 0.6(rain on Oct 31).

0.3 of 0.4(not rain on Oct 31).

Rain on November 2:

Considering rain on November 1, 0.9 probability of rain.

Rain on November 3:

Considering rain on November 2, 0.1 probability of rain.

Find the probability of rain on November 1 and 2, but not on November 3.

Multiplicating the probabilities:

$p = (0.9*0.6+0.3*0.4)*0.9*0.1 = 0.0594$

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.

4 0

2 years ago