A rhombus diagonals form right angles. The diagonals also cut in half the angles
use cosine: cos38 = 
a = 20cos38
a=15.8
Answer:
Bl^2+4Bl*Fh
Step-by-step explanation:
I'm not quite certain what "draw a net" means here. But for part b, we are doing the formula. The bottom part is a square(assumingly so take this with a grain of salt), thus making the base equal to 3*3 cm or 9 cm^2. The triangular faces are each 3*2.24 cm or 6.72 cm^2. We then multiply this by 4 to get 26.88. Thus, the equation is Bl^2(Base length squared)+Bl*Fh(Face height, I forgot the official name sorry about that)*4 for part b.
Answer:
There is no value of x to fit this requirement.
Step-by-step explanation:
The 2 perimeters in terms of x are:
4(x + 3) for the square and
2(x+1) + 2(x +4) for the rectangle
and these need to be equal so
we equate these 2 and solve for x:
4(x + 3) = 2(x+1) + 2(x +4)
4x + 12 = 2x + 2 + 2x + 8
4x + 12 = 4x + 10
4x - 4x = 10 - 12
0 = -2 which is of course absurd so there is no solution to this equation.
The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
The answer is: 3 containers.
Answer:
A. 14,000
Step-by-step explanation:
because 673 rounded would equal 700
and 18 rounded would be 20
so 700x20 would be 14,000
hopefully you understand
and i hope you have a good day :)
