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3 years ago

Multiply and simplify. (3x+5)(2x2−3x+2) Enter your answer, in standard form, in the box.

Mathematics

2 answers:

Sveta_85 [38]3 years ago

7 0

Answer:

$6x^3+x^2-9x+10$

Step-by-step explanation:

We have the product, $(3x+5)(2x^{2}-3x+2)$ .

On simplifying the product, we get,

$(3x+5)(2x^{2}-3x+2)$

i.e. $6x^3-9x^2+6x+10x^2-15x+10$

i.e. $6x^3+x^2-9x+10$

Thus, the standard form of the product $(3x+5)(2x^{2}-3x+2)$ is $6x^3+x^2-9x+10$ .

forsale [732]3 years ago

5 0

Answer:

6x³+x²-9x+10

Step-by-step explanation:

We have given a binomial and a trinomial .We have to find product of binomial and a triomial.

(3x+5)(2x²-3x+2)

Multiplying each term of binomial to trinomial,we get

3x(2x²-3x+2)+5(2x²-3x+2)

Multiplying each term of binomial to each term of trinomial,we get

3x(2x²)-3x(3x)+3x(2)+5(2x²)+5(-3x)+5(2)

6x³-9x²+6x+10x²-15x+10

Gather like terms

6x³-9x²+10x²+6x-15x+10

Adding the coffiecients of like terms

6x³+x²-9x+10 which is the answer.

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Every round in a competition costs 30 diamonds and you get 10 shards. How many diamonds will it cost you to reach 1,024 shards?

Firdavs [7]

Answer:

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Step-by-step explanation:

To get 10 shards, you need to spend 30 diamonds.

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1,024/10 = 102,4

But you can not play 102.4 rounds, you only can play whole numbers, so we need to round it to the next whole number (not the previous one, because in that case, we would get less than 1,024 shards)

Then you need to play 103 rounds.

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2 years ago

HELP ME PLZ answer question below

Ronch [10]

Answer:

11. -2

12. +0.5

Step-by-step explanation:

11. as x increases by 1, y decreases by 2, -2/1 = -2 the ROC is -2 (rate of change)

12. as x increases by 2, y increases by 1, 1/2 = 0.5, ROC is +0.5

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3 years ago

Read 2 more answers

Pls Help! Very Easy! 10 points! Brainliest if you are correct!

SSSSS [86.1K]

We can see that the 33 degrees corresponds to angle A (parallel lines) meaning they’re equal.
This means that 33 + 2x = 5x (5x is the exterior angle, so the other two interior angles’ sum must equal to it)
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3 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

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2 years ago

Simplify the equation (-2.7)0

NikAS [45]

(-2.7)0 = 0 [multiplication of 0 is 0]

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3 years ago