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Zina [86]
3 years ago
10

In triangle QRS, QR is congruent to SR and RT bisects QS. What justification can you give for QRT congruent to SRT and give the

Triangle Congruence Postulate that supports your reason.
Answers:

Midpoint Theorem, SSS

Given, SSS

Definition of a segment bisector; SSS

Definition of an isosceles triangle, SAS,
Mathematics
2 answers:
kow [346]3 years ago
6 0
The answer is <span>Definition of a segment bisector; SSS.
</span>Explanation:

Since RT bisects QS, we have QT congruent to ST. 
 By SSS, we have triangle QRT congruent to triangle SRT
so, since QT is congruent to ST, RT is congruent to RT, and QR is congruent to SR.
All these sides are congruent to each other that gives the proof of "SSS(SIDE, SIDE, SIDE)" 
spayn [35]3 years ago
4 0
<span>Since RT bisects QS, we have QT congruent to ST. Bisect means it cuts QS in half. The we have RT congruent to RT since it is the same. By SSS, we have triangle QRT congruent to triangle SRT since QT is congruent to ST, RT is congruent to RT, and QR is congruent to SR. Each side is congruent to its respective side in the other triangle and that is SSS (side, side, side).</span>
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Step-by-step explanation:

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What is 2*2^3 in expanded form?
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16

Step-by-step explanation:

To solve this question,we will have to understand some symbols in mathematics...

For example,* means ×

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Try this way:
S=S₁-S₂, where S - area of the figure, S₁ - area of the triangle, S₂ - area of the quadrangle.
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3 years ago
Assume that when adults with smartphones are randomly​ selected, 58​% use them in meetings or classes. If 10 adult smartphone us
Tasya [4]

Answer:

79.85% probability that at least 5 of them use their smartphones in meetings or classes.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they use their smartphone during meetings or classes, or they do not. The probability of an adult using their smartphone in these situations are independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that when adults with smartphones are randomly​ selected, 58​% use them in meetings or classes.

This means that p = 0.58

10 adults selected.

This means that n = 10

Find the probability that at least 5 of them use their smartphones in meetings or classes.

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{10,5}.(0.58)^{5}.(0.42)^{5} = 0.2162

P(X = 6) = C_{10,6}.(0.58)^{6}.(0.42)^{4} = 0.2488

P(X = 7) = C_{10,7}.(0.58)^{7}.(0.42)^{3} = 0.1963

P(X = 8) = C_{10,8}.(0.58)^{8}.(0.42)^{2} = 0.1017

P(X = 9) = C_{10,9}.(0.58)^{9}.(0.42)^{1} = 0.0312

P(X = 10) = C_{10,10}.(0.58)^{10}.(0.42)^{0} = 0.0043

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2162 + 0.2488 + 0.1963 + 0.1017 + 0.0312 + 0.0043 = 0.7985

79.85% probability that at least 5 of them use their smartphones in meetings or classes.

3 0
4 years ago
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